How do you divide $(x^4+2x^3+ 5 x^2+6x-32)/(x-4)$ ?

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How do you divide $(x^4+2x^3+ 5 x^2+6x-32)/(x-4)$ ?

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Answer 1 · 2017-06-05T09:32:03

The remainder is $=456$ and the quotient is $=x^3+6x^2+29x+122$

Explanation:

Let's perform the synthetic division

$color(white)(aaaa)$ $4$ $color(white)(aaaaa)$ $|$ $color(white)(aaaa)$ $1$ $color(white)(aaaaaa)$ $2$ $color(white)(aaaaaa)$ $5$ $color(white)(aaaaa)$ $6$ $color(white)(aaaaaaa)$ $-32$
$color(white)(aaaaaaaaaaaa)$ _________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $color(white)(aaaaaa)$ $4$ $color(white)(aaaaaa)$ $24$ $color(white)(aaaa)$ $116$ $color(white)(aaaaaa)$ $488$
$color(white)(aaaaaaaaaaaa)$ ________

$color(white)(aaaa)$ $color(white)(aaaaaaa)$ $|$ $color(white)(aaaa)$ $1$ $color(white)(aaaaa)$ $6$ $color(white)(aaaaaa)$ $29$ $color(white)(aaaa)$ $122$ $color(white)(aaaaaa)$ $color(red)(456)$

$(x^4+2x^3+5x^2+6x-32)/(x-4)=(x^3+6x^2+29x+122)+(456)/(x-4)$

The remainder is $=456$ and the quotient is $=x^3+6x^2+29x+122$

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How do you divide $(x^4+2x^3+ 5 x^2+6x-32)/(x-4)$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you divide (x^4+2x^3+ 5 x^2+6x-32)/(x-4) (x^4+2x^3+ 5 x^2+6x-32)/(x-4) ?

1 Answer

Explanation:

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Impact of this question

How do you divide $(x^4+2x^3+ 5 x^2+6x-32)/(x-4)$ ?