How do you divide x4−2x3−2x2+11x+122x−6?
1 Answer
Jan 7, 2016
Long divide coefficients to find:
x4−2x3−2x2+11x+122x−6=12x3+12x2+12x+7
with remainder
Explanation:
I like to long divide coefficients, but first note that
We find:
x4−2x3−2x2+11x+12x−3=x3+x2+x+14
with remainder
Hence (dividing by
x4−2x3−2x2+11x+122x−6=12x3+12x2+12x+7
with remainder