How do you divide #(x^2+x-1)/(2x + 4)# using polynomial long division?

1 Answer
Leland Adriano Alejandro
May 18, 2016

#(x^2+x-1)/(2x+4)=1/2x-1/2+1/(2x+4)#

Explanation:

We divide polynomials just like we are dividing integers

#" " " " " " " "underline(1/2x-1/2 " " " " "larr )#the quotient
#2x+4" "|~x^2+x-1#
#" " " " " " " "underline(x^2+2x" " " " " " ")#
#" " " " " " " " " "-x-1#
#" " " " " " " " " "underline(-x-2 " " " " ")#
#" " " " " " " " " " " " " "+1 larr "remainder"#

Our final answer will be written

#(x^2+x-1)/(2x+4)=1/2x-1/2+1/(2x+4)#

God bless....I hope the explanation is useful.

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