How do you divide $(x^2 + 7x – 6) / (x-6)$ using polynomial long division?

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How do you divide $(x^2 + 7x – 6) / (x-6)$ using polynomial long division?

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Answer 1 · 2018-08-05T07:54:39

$(x^2+7x-6)=(x-6)(x+13)+72$

Explanation:

Here ,

Dividend $:color(blue)(x^2+7x-6) and$ divisor $: color(red)(x-6$

So ,
$color(white)(..................................)ul(x+13color(white)(.........))larrquotient$
$color(white)(..................)(x-6)$ $|$ $x^2+7x-6$
$color(white)(......)color(violet)((x-6)*xtocolor(white)(......)ul(x^2-6x)$ $color(white)(.......)lArr"subtract"$
$color(white)(........................................0)13x-6$
$color(white)(..........)color(violet)((x-6)*13tocolor(white)(.......)ul(13x-78)$ $color(white)(.......)lArr"subtract"$
$color(white)(....................................................)color(green)(72$ $color(white)(.........)larr"Remainder"$
Hence ,

$(x^2+7x-6)=(x-6)(x+13)+72$

$Quotient :q(x)=x+13$ $"and Remainder " :r(x)=72$

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How do you divide $(x^2 + 7x – 6) / (x-6)$ using polynomial long division?

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How do you divide (x^2 + 7x – 6) / (x-6) (x^2 + 7x – 6) / (x-6) using polynomial long division?

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Explanation:

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How do you divide $(x^2 + 7x – 6) / (x-6)$ using polynomial long division?