How do you divide $(x^2+12x-18)/(x-3)$ ?

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Answer 1 · 2018-03-08T00:59:39

$x + 9$

$x-3$ divided into $x^2+12x-18$

First part of answer is $x$

$x-3$ times $x$ is $x^2-3x$

Subtract from $x^2+12x-18$ to get $9x-18$

Second part will then be $9$

$x-3$ times $9$ is $9x-18$

So answer is $x+9$

How do you divide (x^2+12x-18)/(x-3)(x^2+12x-18)/(x-3)?