How do you divide $\frac{\sqrt{80 w^{3}}}{\sqrt{9}}$ $sqrt(80w^3)/sqrt9$ ?

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Answer 1 · 2015-04-22T15:43:31

Extract the squares from within the square roots

$\frac{\sqrt{80 w^{3}}}{\sqrt{9}}$ $sqrt(80w^3)/(sqrt(9))$

$= \frac{\sqrt{4^{2} w^{2} \cdot 5 w}}{\sqrt{3^{2}}}$ $=sqrt(4^2w^2*5w)/sqrt(3^2)$

$= \frac{4 w}{3} \cdot \sqrt{5 w}$ $=(4w)/3 * sqrt(5w)$

How do you divide √80w3√9sqrt(80w^3)/sqrt9?