How do you divide $\frac{9 x^{3} + x^{2} + 9 x}{x + 1}$ $(9x^3 + x^2 + 9x)/(x+1)$ ?

Question

2169 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-23T16:20:45

$9 x^{2} - 8 x + 1 + \frac{17}{x + 1}$ $9x^2 - 8x + 1 + 17/(x+1)$

Solve using polynomial long division:

enter image source here

Hope this helps!

How do you divide 9x3+x2+9xx+1(9x^3 + x^2 + 9x)/(x+1)?