How do you divide #(9+i)/(-7i)#? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Alan P. Sep 30, 2016 #color(green)(1/7-9/7i)# Explanation: Given #color(white)("XXX")(9+i)/(7i)# Multiplying both the numerator and denominator by#i# #color(white)("XXX")=(9i-1)/(-7)# #color(white)("XXX")=1/7 -9/7i# Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient #(-5+i)/(-7+i)#? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of #12/(5i)#? How do I rationalize the denominator of a complex quotient? How do I divide #6(cos^circ 60+i\ sin60^circ)# by #3(cos^circ 90+i\ sin90^circ)#? How do you write #(-2i) / (4-2i)# in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 2374 views around the world You can reuse this answer Creative Commons License