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How do you divide $\frac{8 x^{3} + 5 x^{2} - 12 x + 10}{x^{2} - 3}$ $(8x^3+5x^2-12x+10)/(x^2-3)$ ?

1 Answer

Apr 29, 2017

Quotient $8 x + 5$ $8x+5$
Remainder $27 x + 10$ $27x+10$

Explanation:

If $f(x)/g(x)=h(x)....i(x)$
So
$(8x^3+5x^2-12x+10)/(x^2-3)=(8x+5).....(27x+10)$

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