How do you divide #(8x^2-10x-7)/(4x+1)#?

1 Answer
Euan S.
Jul 3, 2016

#(8x^2 - 10x - 7)/(4x+1) = 2x - 3 - 4/(4x+1)#

Explanation:

This is very hard to format on here so I'm going to assume you sort of know how to do polynomial long division and just walk you through the steps. I can hand write it and scan it in if you need more help visualising what I'm on about.

Dividing 4x into first term gives 2x.

Multiply #4x+1# by the #2x# and subtract, giving:

#8x^2 - 10x - 7#
#- [8x^2 + 2x]#

#= -12x - 7#

Dividing in again gives -3. Multiply by -3 and subtract:

#-12x-7#
#- [-12x - 3]#

#= -4# which is our remainder.

#(8x^2 - 10x - 7)/(4x+1) = 2x - 3 - 4/(4x+1)#

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