How do you divide $\frac{7 x^{4} - 5 x^{3} - 5 x^{2} + x - 2}{(x + 4)}$ $(7x^4 -5x^3-5x^2+x-2)/((x + 4) )$ ?

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How do you divide $\frac{7 x^{4} - 5 x^{3} - 5 x^{2} + x - 2}{(x + 4)}$ $(7x^4 -5x^3-5x^2+x-2)/((x + 4) )$ ?

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Answer 1 · 2017-01-18T20:13:48

$7 x^{3} - 33 x^{2} + 127 x + 507 - \frac{2030}{x + 4}$ $7x^3-33x^2+127x+507-2030/(x+4)$

Explanation:

$7 x^{4} - 25 x^{3} - 5 x^{2} + x - 2$ $" "7x^4-color(white)(2)5x^3-5x^2+x-2$
$color(red)(7x^3)(x+4) -> ul(7x^4+28x^3) larr" subtract"$
$" "0color(white)(x^2) -33x^3-color(white)(13)5x^2+x-2$
$color(red)(-33x^2)(x+4) ->ul(color(white)(.)-33x^3-132x^2) larr" subtract"$
$" "0+ 127x^2+" "x-2$
$color(red)(127x)(x+4)->ul(" "127x^2+508x) larr" subtract"$
$" "0-507x-color(white)(202)2$
$color(red)(507)(x+4)->ul(" " -507x+2028 ) larr" sub."$
$" "0" " color(green)(-2030)$

The $color(green)(-2030)$ is a remainder so putting it all together we have:

$color(red)(7x^3-33x^2+127x+507)color(green)(-2030/(x+4))$

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How do you divide $\frac{7 x^{4} - 5 x^{3} - 5 x^{2} + x - 2}{(x + 4)}$ $(7x^4 -5x^3-5x^2+x-2)/((x + 4) )$ ?

1 Answer

Explanation:

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How do you divide (7x^4 -5x^3-5x^2+x-2)/((x + 4) )7x4−5x3−5x2+x−2(x+4)(7x^4 -5x^3-5x^2+x-2)/((x + 4) )?

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Explanation:

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How do you divide $\frac{7 x^{4} - 5 x^{3} - 5 x^{2} + x - 2}{(x + 4)}$ $(7x^4 -5x^3-5x^2+x-2)/((x + 4) )$ ?