How do you divide $\frac{6 x^{4} + 12 x + 4}{3 x^{2} + 2 x + 5}$ $(6x^4+12x+4)/(3x^2+2x+5)$ ?

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How do you divide $\frac{6 x^{4} + 12 x + 4}{3 x^{2} + 2 x + 5}$ $(6x^4+12x+4)/(3x^2+2x+5)$ ?

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Answer 1 · 2017-11-02T12:34:11

Taken you to a point where you can continue from. Method is demonstrated.

Explanation:

I am using no value place keepers. Example $0 x^{3}$ $0x^3$

$ddddddddd.dddddddd.dd 6 x^{4} + 0 x^{3} + 0 x^{2} + 12 x + 4$ $color(white)("ddddddddd.dddddddd.dd")6x^4+0x^3+0x^2+12x+4$
$color(magenta)(+2x^2)(3x^2+2x+5) ->color(white)("d") ul(6x^4+4x^3+10x^2 larr" Subtract")$
$color(white)("dddddddddddddddddddddd")0-4x^3 -10x^2+12x+4$
$color(magenta)(-4/3x)(3x^2+2x+5) ->color(white)("dd.dd")ul(-4x^3-8/3x^2-20/3 x larr" Sub." )$
$color(white)("dddddddddddddddddddddddddd") 0 -22/3x^2+56/3x+4$

This should be enough to demonstrate the method. I will let you take over from this point.

SO FAR WE HAVE AS AN ANSWER

$color(white)("d")color(magenta)(2x^2-4/3x + ? + ("remainder")/(3x^2+2x+5)$

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How do you divide $\frac{6 x^{4} + 12 x + 4}{3 x^{2} + 2 x + 5}$ $(6x^4+12x+4)/(3x^2+2x+5)$ ?

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Explanation:

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How do you divide (6x^4+12x+4)/(3x^2+2x+5)6x4+12x+43x2+2x+5(6x^4+12x+4)/(3x^2+2x+5)?

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Explanation:

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How do you divide $\frac{6 x^{4} + 12 x + 4}{3 x^{2} + 2 x + 5}$ $(6x^4+12x+4)/(3x^2+2x+5)$ ?