How do you divide $(6x^3-16x^2+17x-6) / (3x-2)$ using polynomial long division?

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Answer 1 · 2017-12-10T20:43:31

Quotient: $2x^2-4x+3$ and remainder: $0$

$6x^3-16x^2+17x-6$

= $6x^3-4x^2-12x^2+8x+9x-6$

= $2x^2*(3x-2)-4x*(3x-2)+3*(3x-2)$

= $(2x^2-4x+3)*(3x-2)$

Quotient: $2x^2-4x+3$ and remainder: $0$

How do you divide (6x^3-16x^2+17x-6) / (3x-2) (6x^3-16x^2+17x-6) / (3x-2) using polynomial long division?