How do you divide #(5x^2 + 22x + 8)/( 6x+8)#?

1 Answer
Tony B
Feb 10, 2017

#5/6x+23/9 - 112/(54x+72)#

Explanation:

I am afraid you are into fractions with this one!

#" "5x^2+22x+8#
#5/6x(6x+8) ->" "ul(5x^2+40/6x) larr" subtract" #
#" "0+46/3x+8#
#46/(3xx6)(6x+8)->" " ul(46/3x+184/9) larr" subtract"#
#" "0 -112/9#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#(5x^2+22x+8)/(6x+8)" "=" "5/6x+23/9 - 112/(9(6x+8))#

#" "=5/6x+23/9 - 112/(54x+72)#

#color(red)("That was cruel!!!!")#

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