How do you divide $\frac{4 x^{4} - 12 x^{2} - x - 20}{(x^{2} + 4)}$ $(4x^4 -12 x^2-x-20)/((x^2 + 4) )$ ?

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How do you divide $\frac{4 x^{4} - 12 x^{2} - x - 20}{(x^{2} + 4)}$ $(4x^4 -12 x^2-x-20)/((x^2 + 4) )$ ?

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Answer 1 · 2018-07-03T05:39:49

The quotient is $(4 x^{2} - 28)$ $(4x^2-28)$ and the remainder is $(- x + 92)$ $(-x+92)$

Explanation:

Perform a long division.

$a a a a$ $color(white)(aaaa)$ $4 x^{4} - 12 x^{2} - x - 20$ $4x^4-12x^2-x-20$ $a a a a$ $color(white)(aaaa)$ $∣$ $|$ $x^{2} + 4$ $x^2+4$

$a a a a$ $color(white)(aaaa)$ $4 x^{4} + 16 x^{2}$ $4x^4+16x^2$ $a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $∣$ $|$ $4 x^{2} - 28$ $4x^2-28$

$a a a a a a$ $color(white)(aaaaaa)$ $0 - 28 x^{2} - x - 20$ $0-28x^2-x-20$

$a a a a a a a a$ $color(white)(aaaaaaaa)$ $- 28 x^{2} - 0 x - 112$ $-28x^2-0x-112$

$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $+ 0 - x + 92$ $+0-x+92$

The quotient is $(4 x^{2} - 28)$ $(4x^2-28)$ and the remainder is $(- x + 92)$ $(-x+92)$

$\frac{4 x^{4} - 12 x^{2} - x - 20}{x^{2} + 4} = 4 x^{2} - 28 + \frac{- x + 92}{x^{2} + 4}$ $(4x^4-12x^2-x-20)/(x^2+4)=4x^2-28+(-x+92)/(x^2+4)$

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How do you divide $\frac{4 x^{4} - 12 x^{2} - x - 20}{(x^{2} + 4)}$ $(4x^4 -12 x^2-x-20)/((x^2 + 4) )$ ?

1 Answer

Explanation:

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How do you divide (4x^4 -12 x^2-x-20)/((x^2 + 4) )4x4−12x2−x−20(x2+4)(4x^4 -12 x^2-x-20)/((x^2 + 4) )?

1 Answer

Explanation:

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How do you divide $\frac{4 x^{4} - 12 x^{2} - x - 20}{(x^{2} + 4)}$ $(4x^4 -12 x^2-x-20)/((x^2 + 4) )$ ?