How do you divide (4x^2-3x+9)/(x+4)?

1 Answer
Tony B
Jun 14, 2016

A different presentation style

(4x^2-3x+9)/(x+4)" "=" "4x-3+5/(x+4)

Explanation:

" "color(blue)(4x^2-3x+9)
color(magenta)(4x)(x+4)->" "ul(4x^2+16x)" "larr" Subtract"
" " 0-19x
ul(color(magenta)(-19)(x+4)->" "-19x-76" "larr" Subtract"
"Remainder "->" "0-76

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

(4x^2-3x+9)/(x+4)" "=" "4x-19-76/(x+4)

Related questions
See all questions in Division of Polynomials
Impact of this question
1529 views around the world
You can reuse this answer
Creative Commons License