How do you divide #( -3x^3+ x^2-x-72 )/(x - 2 )#?

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How do you divide #( -3x^3+ x^2-x-72 )/(x - 2 )#?

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Answer 1 · 2016-02-27T13:08:05

#(-3x^3+x^2-x-72)/(x-2)#
#=(-3x^2(x-2)-6x^2+x^2-x-72)/(x-2)#
#=(-3x^2(x-2)-5x(x-2)-10x-x-72)/(x-2)#
#=(-3x^2(x-2)-5x(x-2)-11(x-2)-22-72)/(x-2)#
#=-3x^2-5x-11-94/(x-2)#

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How do you divide #( -3x^3+ x^2-x-72 )/(x - 2 )#?

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