How do you divide (-3x^3 - x^2 - 11x + 30)/(2x+2)−3x3−x2−11x+302x+2?

1 Answer
Tony B
Apr 14, 2017

-3/2x^2+x-13/2+43/(2x+2)−32x2+x−132+432x+2

Explanation:

What follows is the 'traditional long division' but in a different format. The processes are exactly the same.

" "-3x^3-x^2-11x+30 −3x3−x2−11x+30
color(magenta)(-3/2x^2)(2x+2)->" "ul(-3x^3-3x^2) larr" subtract"
" "0+2x^2-11x+30
" "color(magenta)(x)(2x+2)->" "ul(2x^2+2x) larr" subtract"
" "0-13x+30
color(white)(.)color(magenta)(-13/2)(2x+2)->" " ul(-13x-13)
color(magenta)(" Remainder "->0+43)

color(magenta)(-3/2x^2+x-13/2+43/(2x+2)

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