How do you divide ( -3x^3+ 6x^2-13x-5 )/(x + 1 )?
1 Answer
Feb 21, 2018
Explanation:
"one way is to use the divisor as a factor in the numerator"
"consider the numerator"
color(red)(-3x^2)(x+1)color(magenta)(+3x^2)+6x^2-13x-5
=color(red)(-3x^2)(x+1)color(red)(+9x)(x+1)color(magenta)(-9x)-13x-5
=color(red)(-3x^2)(x+1)color(red)(+9x)(x+1)color(red)(-22)(x+1)color(magenta)(+22)-5
=color(red)(-3x^2)(x+1)color(red)(+9x)(x+1)color(red)(-22)(x+1)+17
"quotient "=color(red)(-3x^2+9x-22)," remainder "=17
rArr(-3x^3+6x^2-13x-5)/(x+1)
=-3x^2+9x-22+17/(x+1)
