How do you divide $\frac{3 x^{3} - 6 x^{2} + 13 x - 4}{x - 3}$ $(3x^3-6x^2+13x-4)/(x-3)$ ?

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How do you divide $\frac{3 x^{3} - 6 x^{2} + 13 x - 4}{x - 3}$ $(3x^3-6x^2+13x-4)/(x-3)$ ?

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Answer 1 · 2016-07-28T12:21:35

$3 x^{2} + 3 x + 22 + \frac{62}{x - 3}$ $3x^2+3x+22+62/(x-3)$

Explanation:

color(white)(.)
$3 x^{3} - 6 x^{2} + 13 x - 4$ $" "3x^3-6x^2+13x-4$
$" "color(magenta)(3x^2)(x-3) ->" "ul(3x^3-9x^2)" "larr" Subtract"$
$" "0color(white)(.)+3x^2+13x-4$
$" "color(magenta)(3x)(x-3)->" "ul(3x^2-9x) larr" Subtract"$
$" "0+22x-4$
$" "color(magenta)(22)(x-3) ->" "ul(22x-66) larr" Subtract"$
$" "0color(magenta)(+62 larr" Remainder")$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$3x^2+3x+22+62/(x-3)$

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How do you divide $\frac{3 x^{3} - 6 x^{2} + 13 x - 4}{x - 3}$ $(3x^3-6x^2+13x-4)/(x-3)$ ?

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How do you divide (3x^3-6x^2+13x-4)/(x-3) 3x3−6x2+13x−4x−3(3x^3-6x^2+13x-4)/(x-3) ?

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How do you divide $\frac{3 x^{3} - 6 x^{2} + 13 x - 4}{x - 3}$ $(3x^3-6x^2+13x-4)/(x-3)$ ?