How do you divide #(3x^3 + 5x^2 -3 x + 15) / (3x^2 -4x+12)#?

1 Answer
Gió
Feb 8, 2016

I tried to explain as much as possible the division where I got #(x+3)# with a remainder of #-3x-21#:

Explanation:

I used the division of polynomials and added some explanation (hoping they are understandable!):
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From the picture, I divide the first time and got #x# and then (after subtracting and using #15#) I divide again and got #+3#.

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