How do you divide $\frac{3 x^{3} + 5 x^{2} - 3 x + 15}{3 x^{2} - 4 x + 12}$ $(3x^3 + 5x^2 -3 x + 15) / (3x^2 -4x+12)$ ?

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How do you divide $\frac{3 x^{3} + 5 x^{2} - 3 x + 15}{3 x^{2} - 4 x + 12}$ $(3x^3 + 5x^2 -3 x + 15) / (3x^2 -4x+12)$ ?

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Answer 1 · 2016-02-08T14:01:08

I tried to explain as much as possible the division where I got $(x + 3)$ $(x+3)$ with a remainder of $- 3 x - 21$ $-3x-21$ :

Explanation:

I used the division of polynomials and added some explanation (hoping they are understandable!):
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From the picture, I divide the first time and got $x$ $x$ and then (after subtracting and using $15$ $15$ ) I divide again and got $+ 3$ $+3$ .

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How do you divide $\frac{3 x^{3} + 5 x^{2} - 3 x + 15}{3 x^{2} - 4 x + 12}$ $(3x^3 + 5x^2 -3 x + 15) / (3x^2 -4x+12)$ ?

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How do you divide (3x^3 + 5x^2 -3 x + 15) / (3x^2 -4x+12)3x3+5x2−3x+153x2−4x+12(3x^3 + 5x^2 -3 x + 15) / (3x^2 -4x+12)?

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Explanation:

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How do you divide $\frac{3 x^{3} + 5 x^{2} - 3 x + 15}{3 x^{2} - 4 x + 12}$ $(3x^3 + 5x^2 -3 x + 15) / (3x^2 -4x+12)$ ?