How do you divide $\frac{- 3 x^{3} + 4 x^{2} + 12 x + 9}{x - 2}$ $( -3x^3+ 4x^2 + 12x + 9 )/(x - 2 )$ ?

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How do you divide $\frac{- 3 x^{3} + 4 x^{2} + 12 x + 9}{x - 2}$ $( -3x^3+ 4x^2 + 12x + 9 )/(x - 2 )$ ?

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Answer 1 · 2017-02-02T13:51:54

$\frac{- 3 x^{3} + 4 x^{2} + 12 x + 9}{x - 2} = - 3 x^{2} - 2 x + 8 + \frac{25}{x - 2}$ $(-3x^3+4x^2+12x+9)/(x-2) " "=" "-3x^2-2x+8+25/(x-2)$

Explanation:

$- 3 x^{3} + 4 x^{2} + 12 x + 9 ............checked$ $" "-3x^3+4x^2+12x+9" ............checked"$
$color(red)(-3x^2)(x-2)-> ul(-3x^3+6x^2) larr" subtract .........corrected"$
$" "0-2x^2+12x+9$
$color(red)(-2x)(x-2)->" "ul(-2x^2+4x)larr" subtract"$
$" "0+8x+9$
$color(red)(+8)(x-2)->" "ul(8x-16)larr" subtract"$
$" "0color(red)(+25 larr" remainder")$

$(-3x^3+4x^2+12x+9)/(x-2) " "=" "color(red)(-3x^2-2x+8+)color(red)(25)/(x-2)$

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Checked in Maple:

Tony B

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How do you divide $\frac{- 3 x^{3} + 4 x^{2} + 12 x + 9}{x - 2}$ $( -3x^3+ 4x^2 + 12x + 9 )/(x - 2 )$ ?

1 Answer

Explanation:

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How do you divide ( -3x^3+ 4x^2 + 12x + 9 )/(x - 2 )−3x3+4x2+12x+9x−2( -3x^3+ 4x^2 + 12x + 9 )/(x - 2 )?

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Explanation:

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How do you divide $\frac{- 3 x^{3} + 4 x^{2} + 12 x + 9}{x - 2}$ $( -3x^3+ 4x^2 + 12x + 9 )/(x - 2 )$ ?