How do you divide #(3x^2 - 10x) / (x - 6)#? Precalculus Real Zeros of Polynomials Long Division of Polynomials 1 Answer GiĆ³ Jul 7, 2016 I found: #(3x^2-10x)/(x-6)=(3x+8)(x-6)+48# Explanation: Have a look: Answer link Related questions What is long division of polynomials? How do I find a quotient using long division of polynomials? What are some examples of long division with polynomials? How do I divide polynomials by using long division? How do I use long division to simplify #(2x^3+4x^2-5)/(x+3)#? How do I use long division to simplify #(x^3-4x^2+2x+5)/(x-2)#? How do I use long division to simplify #(2x^3-4x+7x^2+7)/(x^2+2x-1)#? How do I use long division to simplify #(4x^3-2x^2-3)/(2x^2-1)#? How do I use long division to simplify #(3x^3+4x+11)/(x^2-3x+2)#? How do I use long division to simplify #(12x^3-11x^2+9x+18)/(4x+3)#? See all questions in Long Division of Polynomials Impact of this question 1276 views around the world You can reuse this answer Creative Commons License