How do you divide (2x^5-3x^3+2x-12)/(-3x^2+3)?

1 Answer
George C.
Jul 29, 2018

(2x^5-3x^3+2x-12)/(-3x^2+3)=-2/3x^3+1/3x+(x-12)/(-3x^2+3)

Explanation:

(2x^5-3x^3+2x-12)/(-3x^2+3)

=-1/3(2x^5-3x^3+2x-12)/(x^2-1)

=-1/3(2x^5-2x^3-x^3+x+x-12)/(x^2-1)

=-1/3((2x^3-x)(x^2-1)+x-12)/(x^2-1)

=-1/3(2x^3-x+(x-12)/(x^2-1))

=-2/3x^3+1/3x+(x-12)/(-3x^2+3)

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