How do you divide #(2x^4+3x^2+12x+5)/(-x^2+3)#?

2 Answers
Shantelle
Jul 23, 2018

#-2x^2 - 9 + (12x+32)/(-x^2+3)#

Explanation:

Solve using polynomial long division:

enter image source here

Hope this helps!

Tony B
Jul 23, 2018

#-2x^2-9+(12x+32)/(-x^2+3)#

Explanation:

Using place keepers of no value. Example: #0x^3#

#color(white)("dddddddddd.ddddddd")2x^4+0x^3+3x^2+12x+5#
#color(magenta)(-2x^2)(-x^2+3) ->ul(+2x^4+0x^3-6x^2larr" Subtract") #
#color(white)("dddddddddddddddddd") 0color(white)(".d") +0color(white)("dd")+9x^2+12x+5#
#color(white)(".d")color(magenta)(-9)(-x^2+3)-> color(white)("dddddddd..d")ul(+9x^2+0x-27larr"Sub")#
#color(magenta)(color(white)("ddd")"Remainder "->color(white)("ddddddddddddd")0+12x+32)#

#-2x^2-9+(12x+32)/(-x^2+3)#

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