How do you divide $\frac{2 x^{3} - x^{2} + 7 x + 15}{2 x - 5}$ $(2x^3-x^2+7x+15)/(2x-5)$ ?

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Answer 1 · 2017-09-13T00:06:53

$x^{2} - 2 x + 8.5$ $x^2-2x+8.5$ , with a remainder of $27.5$ $27.5$

Using polynomial long division:

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How do you divide 2x3−x2+7x+152x−5(2x^3-x^2+7x+15)/(2x-5) ?