How do you divide $(2 x^{3} - x^{2} + 5) \div (x - 2)$ $(2x^3-x^2+5)÷(x-2)$ ?

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How do you divide $(2 x^{3} - x^{2} + 5) \div (x - 2)$ $(2x^3-x^2+5)÷(x-2)$ ?

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Answer 1 · 2015-09-27T18:58:13

Quotient = $2 \cdot x^{2} + 3 \cdot x + 6$ $2*x^2+3*x+6$
Remainder = $17$ $17$

Explanation:

Without omitting any degrees of the polynomial, the dividend is $2 \cdot x^{3} - x^{2} + 0 \cdot x + 5$ $2*x^3 - x^2 + 0*x + 5$ and the divisor is $x - 2$ $x - 2$
Now using the long division method step by step
Q = quotient
R = remainder
Q0 = 0
R0 = $2 \cdot x^{3} - x^{2} + 0 \cdot x + 5$ $2*x^3 - x^2 + 0*x + 5$
Q1 = $2 \cdot x^{2}$ $2*x^2$
R1 = $+ 3 x^{2} + 0 \cdot x + 5$ $+3x^2+0*x+5$
Q2 = $2 \cdot x^{2} + 3 x$ $2*x^2+3x$
R2 = $+ 6 \cdot x + 5$ $+6*x+5$
Q3 = $2 \cdot x^{2} + 3 \cdot x + 6$ $2*x^2+3*x+6$
R3 = $17$ $17$

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How do you divide $(2 x^{3} - x^{2} + 5) \div (x - 2)$ $(2x^3-x^2+5)÷(x-2)$ ?

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How do you divide $(2 x^{3} - x^{2} + 5) \div (x - 2)$ $(2x^3-x^2+5)÷(x-2)$ ?