How do you divide $(-2x^3-2x^2+43x+32)/(x-5)$ ?

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How do you divide $(-2x^3-2x^2+43x+32)/(x-5)$ ?

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Answer 1 · 2016-01-19T13:43:03

$(-2x^2 -12x - 17) -53/(x-5)$

Explanation:

Divide $x-5$ into the first term, giving $-2x^2$ . Multiply $x-5$ $-2x^2$ and subtract this from the original numerator. Repeat this process until there is an indivisible remainder.
Calculation

Thus the answer is $(-2x^2 -12x - 17) -53/(x-5)$

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How do you divide $(-2x^3-2x^2+43x+32)/(x-5)$ ?

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Explanation:

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Science

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How do you divide (-2x^3-2x^2+43x+32)/(x-5) (-2x^3-2x^2+43x+32)/(x-5) ?

1 Answer

Explanation:

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How do you divide $(-2x^3-2x^2+43x+32)/(x-5)$ ?