How do you divide $(2x^2 + x – 16) /(x – 3)$ ?

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Answer 1 · 2018-03-30T03:33:46

$(2x^2+x-16)/(x-3)=2x+7+5/(x-3)$

I would use synthetic division.

Drawing from Algebra By Hand(TM)

This means that

$(2x^2+x-16)/(x-3)=2x+7+5/(x-3)$

How do you divide (2x^2 + x – 16) /(x – 3)(2x^2 + x – 16) /(x – 3)?