How do you divide (2x^2+8x+16) / (x-4) ?

1 Answer
Jun 23, 2018

2x+16+80/(x+4)

Explanation:

"one way is to use the divisor as a factor in the numerator"

"consider the numerator"

color(red)(2x)(x-4)color(magenta)(+8x)+8x+16

=color(red)(2x)(x-4)color(red)(+16)(x-4)color(magenta)(+64)+16

=color(red)(2x)(x-4)color(red)(+16)(x-4)+80

"quotient "=color(red)(2x+16)," remainder "=80

(2x^2+8x+16)/(x-4)=2x+16+80/(x-4)