How do you divide $( -14x^2 + 4x^2 + 19 +4x)/(2x-5)$ ?

Question

How do you divide $( -14x^2 + 4x^2 + 19 +4x)/(2x-5)$ ?

1 Answer

Impact of this question

1726 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-04T11:37:24

$color(magenta)( (-14x^3+4x^2+4x+19)/(2x-5) = -7x^2-15.5x-36.75$ and remainder $color(magenta)(-164.75/(2x-5)$

Explanation:

$(-14x^2+4x^2+19+4x)/(2x-5)$

I think $-14x^2$ should be $-14x^3$

$:.= (-14x^3+4x^2+4x+19)/(2x-5)$

$color(white)(......)color(white)(......)-7x^2-15.5x-36.75$
$2x-5|overline(-14x^3+4x^2+4x+19)$
$color(white)(.............)ul(-14x^3+35x^2)$
$color(white)(......................)-31x^2+4x$
$color(white)(.......................)ul(-31x^2+77.5x)$
$color(white)(..................................)-73.5x+19$
$color(white)(....................................)ul(-73.5x+183.75)$
$color(white)(................................................)-164.75$

$color(magenta)( (-14x^3+4x^2+4x+19)/(2x-5) = -7x^2-15.5x-36.75$ and remainder $color(magenta)(-164.75/(2x-5)$

Science

Math

Humanities

... and beyond

How do you divide $( -14x^2 + 4x^2 + 19 +4x)/(2x-5)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you divide ( -14x^2 + 4x^2 + 19 +4x)/(2x-5)( -14x^2 + 4x^2 + 19 +4x)/(2x-5)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you divide $( -14x^2 + 4x^2 + 19 +4x)/(2x-5)$ ?