How do you differentiate #y=sqrt(x + 1)/root3( x^4) #?

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How do you differentiate #y=sqrt(x + 1)/root3( x^4) #?

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Answer 1 · 2018-06-01T14:41:07

#(3(x+1)^(-1/2)*x^(4/3)-8(x+1)^(1/2)*x^(1/3))/(6x^(8/3))#

Explanation:

By the Quotient rule we get
#(1/2*(x+1)^(-1/2)*x^(4/3)-2(x+1)^(1/2)*4/3*x^(1/3))/x^(8/3)#
Multiplying numerator and denominator by #6#
#(3(x+1)^(-1/2)*x^(4/3)-8(x+1)^(1/2)*x^(1/3))/(6*x^(8/3))#

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How do you differentiate #y=sqrt(x + 1)/root3( x^4) #?

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