How do you differentiate #y=ln(3xe^(1-x))#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Ratnaker Mehta Jul 31, 2018 # (1-x)/x#. Explanation: #y=ln(3xe^(1-x))#. Using the usual rules of log function, we have, #y=ln3+lnx+lne^(1-x), or, # #y=ln3+lnx+(1-x)lne=ln3+lnx+1-x#. #:. dy/dx=0+1/x+0-1#. # rArr dy/dx=(1-x)/x#, as Respected Sonnhard has derived! Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 3226 views around the world You can reuse this answer Creative Commons License