How do you differentiate #y = cos^3(3x+1)#?

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How do you differentiate #y = cos^3(3x+1)#?

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Answer 1 · 2015-04-07T21:36:16

I would use the Chain Rule deriving the #()^3# first and then the #cos# and then the argument as:
#y'=3cos^2(3x+1)*[-sin(3x+1)]*3=-9cos^2(3x+1)sin(3x+1)#

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How do you differentiate #y = cos^3(3x+1)#?

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