How do you differentiate #y = cos^2 (x^2 - 3x)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Sasha P. Sep 26, 2015 #y'=(3-2x)sin2(x^2-3x)# Explanation: #y'=2cos(x^2-3x) * (-sin(x^2-3x)) * (2x-3)# #y'=(3-2x)sin2(x^2-3x)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 1579 views around the world You can reuse this answer Creative Commons License