How do you differentiate #y = cos^2 (x^2)#?

Question

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Answer 1 · 2015-04-16T17:35:43

#y'=-4xcos(x^2)(sinx^2)#

Solution

#y=cos^2(x^2))#

Differentiating both sides with respect to # 'x'#

#y'=d/dxcos^2(x^2))#

#y'=2cos(x^2)d/dx(cosx^2)#

#y'=2cos(x^2)(-sinx^2)d/dx(x^2)#

#y'=2cos(x^2)(-sinx^2)(2x)#

#y'=-4xcos(x^2)(sinx^2)#