How do you differentiate #y=(8x^3-6x^2-4)/(2x^2)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Eddie Sep 26, 2016 #y'=4+ 4/x^3# Explanation: re- write #y=(8x^3-6x^2-4)/(2x^2)# as #y=4x-3-2/x^2# and apply the power rule #d/dx (x^n) = n x ^ (n-1)# to get #y'=4+ 4/x^3# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1301 views around the world You can reuse this answer Creative Commons License