How do you differentiate #y=4/cosx#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Eddie Jul 18, 2016 #= 4 sec x tan x# Explanation: #d/dx (4/cosx)# #= 4 d/dx ((cosx)^(-1))# #= 4 (-1) (cosx)^(-2) d/dx (cos x)# #= -4 (cosx)^(-2) (- sin x)# #= 4 sin x/ (cos^2x) # #= 4 sec x tan x# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1646 views around the world You can reuse this answer Creative Commons License