How do you differentiate #y = 2/(e^(x) + e^(-x))#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Massimiliano Apr 14, 2015 In this way, remebering the division rule: #y'=(0*(e^x+e^-x)-2*(e^x+e^-x*(-1)))/(e^x+e^-x)^2=# #=(2(e^-x-e^x))/(e^x+e^-x)^2#. Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1426 views around the world You can reuse this answer Creative Commons License