How do you differentiate #x^5+2x^4.3+1/4x^(1/3)#?

1 Answer
Aditya Banerjee.
Nov 2, 2016

Differentiating #x^5+2x^4.3+1/4x^(1/3)# comes to be #5x^4+8.6x^3.3+1/12x^(-2/3).#

Explanation:

Let, #y=x^5+2x^4.3+1/4x^(1/3)=f(x).#

#:.#Differentiating #y # with respect to #x#,

#d/(dx)(y)=dy/dx#.
#:.dy/dx=d/(dx)(x^5+2x^4.3+1/4x^(1/3)).#
#:.dy/dx=5*x^(5-1)+2*4.3*x^(4.3-1)+1/4*1/3*x^(1/3-1).#
#:.dy/dx=5x^4+8.6x^3.3+1/12x^(-2/3).# (answer).

Related questions
See all questions in Power Rule
Impact of this question
1401 views around the world
You can reuse this answer
Creative Commons License