How do you differentiate #(x+1)/(x-1)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Sonnhard Jun 9, 2018 #-2/(x-1)^2# Explanation: After the Quotient rule #(u/v)'=(u'v-uv')/v^2# we get #f'(x)=(x-1-(x+1))/(x-1)^2=-2/(x-1)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 47462 views around the world You can reuse this answer Creative Commons License