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How do you differentiate #u=root5(t)+4sqrt(t^5)#?

1 Answer

Dec 24, 2016

#(du)/(dt)=1/(5t^(4/5))+2/sqrt(t^5)#

Explanation:

#u=t^(1/5)+4(t^5)^(1/2)#

If #y=ax^n# then the derivative, #dy/dx=nax^(n-1)#

Using this, #(du)/(dt)=1/5t^(-4/5)+4(1/2)(t^5)^(-1/2)=1/(5t^(4/5))+2/sqrt(t^5)#

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