How do you differentiate #s=(1+sint)/(1+tant)#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer 1s2s2p Dec 18, 2017 #s'=(cost(1+tant)-sec^2t(1+sint))/(1+tant)^2# Explanation: #s=(1+sint)/(1+tant)=u/v# #s'=(vu'-uv')/v^2# #u=1+sint# #u'=cost# #v=1+tant# #v'=sec^2t# #s'=(cost(1+tant)-sec^2t(1+sint))/(1+tant)^2# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 1840 views around the world You can reuse this answer Creative Commons License