How do you differentiate #log(8x-1)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions without Base e 1 Answer Bdub Mar 31, 2017 see below Explanation: Use the formula below to find the derivative #color(red)(d/dx(log_bf(x))=1/(f(x)ln b) * f'(x)# #y=log (8x-1)# #color(blue)(y'=1/((8x-1)ln10)*8# #color(blue)(y'=8/((8x-1)ln10)# Answer link Related questions What is the derivative of #f(x)=log_b(g(x))# ? What is the derivative of #f(x)=log(x^2+x)# ? What is the derivative of #f(x)=log_4(e^x+3)# ? What is the derivative of #f(x)=x*log_5(x)# ? What is the derivative of #f(x)=e^(4x)*log(1-x)# ? What is the derivative of #f(x)=log(x)/x# ? What is the derivative of #f(x)=log_2(cos(x))# ? What is the derivative of #f(x)=log_11(tan(x))# ? What is the derivative of #f(x)=sqrt(1+log_3(x)# ? What is the derivative of #f(x)=(log_6(x))^2# ? See all questions in Differentiating Logarithmic Functions without Base e Impact of this question 1821 views around the world You can reuse this answer Creative Commons License