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How do you differentiate #log 4^(x^2)#?

1 Answer

Shwetank Mauria

Oct 18, 2016

#d/(dx)log4^(x^2)=1.2042x#

Explanation:

#log4^(x^2)=x^2log4#

Hence #d/(dx)log4^(x^2)=d/(dx)(x^2log4)#

= #log4*d/(dx)x^2#

= #2xlog4#

= #2x xx0.6021#

= #1.2042x#

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