How do you differentiate #h(x)=(1-cosx)/sinx# using the quotient rule? Calculus Basic Differentiation Rules Quotient Rule 1 Answer t0hierry · Jim H Nov 29, 2016 #(1-cosx)/sin^2x# Explanation: #h = f/g# Then #h' = \frac{gf' - fg'}{g^2} = [sin^2x - (1-cosx)cosx]/sin^2 x = (1-cosx)/sin^2x# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 2611 views around the world You can reuse this answer Creative Commons License