How do you differentiate # g(x)= (2x)/(x-1)#?

Question

How do you differentiate # g(x)= (2x)/(x-1)#?

1 Answer

Impact of this question

4501 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-11T18:55:01

#(-2)/(x-1)^2#

Explanation:

We know that,
#color(red)(d/(dx)(u/v)=(v*u^'-u*v^"')/v^2)#
#y=(2x)/(x-1)=>(dy)/(dx)=((x-1)(2)-(2x)(1))/(x-1)^2#
#(dy)/(dx)=(cancel(2x)-2-cancel(2x))/(x-1)^2=(-2)/(x-1)^2#

Science

Math

Humanities

... and beyond

How do you differentiate # g(x)= (2x)/(x-1)#?

1 Answer

Explanation:

Related questions

Impact of this question