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How do you differentiate #G(x)=(1/2x)^5#?

1 Answer

Shaikh A. · Steve M

Dec 5, 2016

# (dG)/dx=5/32 x^4#

Explanation:

if #y=x^n# then #dy/dx=nx^(n-1)#

In our problem
#G(x)=(1/2)^5 x^5#
#G(x)=(1/32) x^5#

# :. (dG)/dx=(1/32)(5x^(5-1))#
# :. (dG)/dx=5/32 x^4#

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