How do you differentiate #g(t)=(t-sqrtt)/(t^(1/3))#?
1 Answer
Dec 2, 2016
I would rewrite to avoid the quotient rule.
Explanation:
# = t/t^(1/3) - t^(1/2)/t^(1/3)#
# = t^(1-1/3) - t^(1/2-1/3)#
# = t^(2/3) - t^(1/6)#
# = 2/(3root(3)x) - 1/(6 root(6)(x^5))#
If you want a single ratio for the derivative, use
# = (4x-1)/(6root(6)(x^5))#
