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How do you differentiate #g(t)= 7/sqrt(t)#?

1 Answer

Nov 15, 2016

#g'(t)=(-7)/(2t^(3/2))#

Explanation:

#g(t)=7/(sqrtt)#

This can be solved multiple ways, such as using the quotient rule, or using the power rule. I prefer the power rule so I will rewrite #g(t)#:

#g(t)=7/(t^(1/2))#
#g(t)=7t^(-1/2)#

Now to differentiate #g(t)#, use the power rule:

#g'(t)=(-1/2)(7)(t^(-3/2))#
#g'(t)=(-7/2)(t^(-3/2))#

#g'(t)=(-7)/(2t^(3/2))#

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